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TOPIC: PHP form validation problem?

PHP form validation problem? 13 years 3 months ago #382

  • simy202
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I\'m making one form using php, so validation is using PHP too,
I m posting the value in the same form and then trying to insert into mysql..look below.. I encountered the problem
<form method=\"post\" enctype=\"multipart/form-data\" name=\"form1\" id=\"form1\">

Name : <input type=\"text\" name=\"t1\" id=\"t1\" />
Contact : <input type=\"text\" name=\"t2\" id=\"t2\" />

<span class=\"err\" ></span>

<input type=\"submit\" name=\"s1\" id=\"s1\" />  

if($_POST[\"t1\"] == \"\")
$err = \"Enter Your name\";

echo \"<script language=javascript>\" . \"alert(\'Enter your name\')\" . \"</script>\";
echo \"<script language=javascript>\" . \"document.getElementById(\'t1\').focus();\" . \"</script>\";
else if($_POST[\"t2\"] == \"\")
$err = \"Enter Your Contact Number\";
echo \"<script language=javascript>\" . \"alert(\'Enter your contact number\')\" . \"</script>\";

echo \"<span style=color:red> $err</span>\";


now what problem m facing here when i click on the \"Submit\" button i m getting the Error messages but the page is redirecting the i have to write all values all over again ..

suppose i have already wrriten a \"NAME(t1)\" but didnt write a CONTACT NUMBER(t2) then after m clicking on the SUBMIT button when i do this my page redirecting, m getting the second error \"write your contact number\" but i have to write all the values like NAME etc all over again ..

so my page is returning to true .. not false .

do you know how to set \"return false\" through php just like we do using javascript .. i cant use javascript for this .. have to use php in this .. plz help me ..

thank you ..

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Re: PHP form validation problem? 13 years 3 months ago #383

  • ragskarnam
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This looks to me a generic PHP question and nothing related to web2cal. You will probably get more help by posting in a php forum. anyways, here is my attempt at this, pardon me if I mis understood u.

If you want to retain user input and validate, why would you want to submit the form? instead do the validation using ajax.
Change your submit button to a regular button
input type=\"submit\" name=\"s1\" id=\"s1\"
input type=\"button\" onclick=\"submitWithAjax()\" name=\"s1\" id=\"s1\"

Now implement submitWithAjax using any of the jquery ajax functions

Hope this helps

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